SOLUTION: Please help me find the perimeter of the problem posted in the link. Thank you, Jimmy Hopkins http://2.bp.blogspot.com/-Z0nGdpqcT8s/Tg_zIhWtOYI/AAAAAAAAAAc/nElH41

SOLUTION: Please help me find the perimeter of the problem posted in the link. Thank you, Jimmy Hopkins http://2.bp.blogspot.com/-Z0nGdpqcT8s/Tg_zIhWtOYI/AAAAAAAAAAc/nElH41_Azng/s320/I

Question 466688: Please help me find the perimeter of the problem posted in the link. Thank you,
Jimmy Hopkins
http://2.bp.blogspot.com/-Z0nGdpqcT8s/Tg_zIhWtOYI/AAAAAAAAAAc/nElH41_Azng/s320/IMG_20110702_213152.jpg
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
The sum of the four horizontal-facing sides on top (labeled 2, 2, 2, unknown) is 11, because if we assume all angles are right angles, we can "slide" the sides over to produce a long side, length 11 cm (only if we had to!). This implies that the unknown horizontal sides is 11 - 2 - 2 - 2 = 5.

Each of the unknown vertical sides is equal to the difference between the two labeled sides, or 2 cm. We can label all the unknown vertical sides and find the perimeter.

I could add up the perimeter by grouping sides together, but in simplicity's sake of using words to type this up instead of diagrams, I will add each side individually, going clockwise.

Perimeter = 11 + 5 + 2 + 2 + 2 + 2 + 2 + 2 + 5 + 3 = 36 cm
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