SOLUTION: 3x^2+13x=10 3x^2+13x-10=0 9+1+13x-10=0 13x=0 x=-13 Could you please help me? Am I even close? Thank you, Michelle

Algebra ->  Algebra  -> Equations -> SOLUTION: 3x^2+13x=10 3x^2+13x-10=0 9+1+13x-10=0 13x=0 x=-13 Could you please help me? Am I even close? Thank you, Michelle      Log On

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Question 45883: 3x^2+13x=10
3x^2+13x-10=0
9+1+13x-10=0
13x=0
x=-13
Could you please help me? Am I even close?
Thank you, Michelle
Found 2 solutions by Nate, Earlsdon:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
I have no idea what you are trying to do to solve this. It seems like you fill in random numbers. How does 13x = 0 turn into x = -13? Here:
3x^2 + 13x = 10
3x^2 + 13x - 10 = 0 find the sum of two factors of the product of (3) and (-10) that sum to (13) ~~~> they are 15 and -2
3x^2 + 15x - 2x - 10 = 0
(3x^2 + 15x) + (-2x - 10) = 0
3x(x + 5) - 2(x + 5) = 0
(3x - 2)(x + 5) = 0
3x - 2 = 0
3x = 2
x = 2/3
and
x + 5 = 0
x = -5
graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C3x%5E2+%2B+13x+-10%29

Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
3x%5E2%2B13x+=+10 Subtract 10 from both sides of the equation.
3x%5E2%2B13x-10+=+0 Factor the equation.
%283x-2%29%28x%2B5%29+=+0 Apply the zero products principle.
3x-2+=+0 and/or x%2B5+=+0
If 3x-2+=+0 then 3x+=+2 and x+=+2%2F3
If x%2B5+=+0 then x+=+-5
The roots are:
x+=+2%2F3
x+=+-5