SOLUTION: Give the equation of the specified asymptote(s). Horizontal asymptote: h(x) = 4x^2-2x-9/(5x^2-5x+9)

Question 45563: Give the equation of the specified asymptote(s).
Horizontal asymptote: h(x) = 4x^2-2x-9/(5x^2-5x+9)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Horizontal asymptote: h(x) = 4x^2-2x-9/(5x^2-5x+9)
Method:
1. Determine the highest power term while looking at the
numeator and the denominator.
Your highest power is x^2, and it is in both numerator and denominator.
2. Write a fraction using the coefficients of that highest power.
Your fraction is 4/5
3. The horizontal asymptote is y=4/5
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Your answer turned out to be a specific value and not equal to zero.
-----------------------------------------
If you have y=[2x^2......]/[3x + 5] the fraction would be 2/0 which
does not exist, indicating you have no horizontal asymptote.
------------------------------------------
If you have [3x+5]/[2x^2.....] the fraction would be 0/2 and
the horizontal asymptote would be y=0
==========================================
Cheers,
Stan H>
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