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Write an equation of the line containing the given point and parallel to the given line.
Express your answer in the form y=mx+b
(-6,7); 2x=9y+8
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The solution and the answer in the post by @mananth both are incorrect.
They are incorrect, since @mananth permanently rounds rational fractions to decimal fractions
even when it is not allowed and ruins the precise form of equations.
So, I came to make the job in a right way as it SHOULD be done.
Any line parallel to 2x = 9y + 8 has the form
2x = 9y + c, (1)
where 'c' is a real constant. To find 'c', we simply insert coordinates (-6,7) into equation (1)
2*(-6) = 9*7 + c,
-12 - 63 = c,
c = -75.
Thus equation (1) takes the form
2x = 9y - 75. (2)
To get the form y = mx + b, we express 'y' from equation (2)
y = + ,
or, which is the same
y = + 8. (3)
So, the slope of the sough line is m = and its equation is y = + 8.
Solved correctly.