SOLUTION: substitution method 4p-2q=16 5p+7q=1

SOLUTION: substitution method 4p-2q=16 5p+7q=1

Algebra.Com

Question 44363: substitution method
4p-2q=16
5p+7q=1
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
MULTIPLY UQ. #1 BY 7 & EQ. #2 BY 2 WE GET
28P-14Q=112
10P+14Q=2 NOW ADD THESE TWO EQ.
------------
38P=114 OR P=114/38 OR P=3 THEN 4*3-2Q=16 OR 12-2Q=16 OR -2Q=4 OR Q=4/-2 OR
Q=-2
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