SOLUTION: please help with this, Find ALL solutions of the equation. I need to show all possible solutions. thanks 9x^4 - 24x^3 + 16x^2 = 0 thanks

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Question 44173This question is from textbook College Algebra
: please help with this,
Find ALL solutions of the equation. I need to show all possible solutions. thanks
9x^4 - 24x^3 + 16x^2 = 0
thanksThis question is from textbook College Algebra

Answer by adamchapman(301) About Me  (Show Source):
You can put this solution on YOUR website!
9x%5E4+-+24x%5E3+%2B+16x%5E2+=+0
divide both sides by x%5E2
9x%5E2+-+24x+%2B+16+=+0
Now you have a quadratic that can be solved using x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Note that because you have divided everything by x%5E2 every solution you obtain will have an opposite of that solution attatched to it.
For example, if you obtained x=1 and x=2 from the quadratic, solutions x=-1 and x=-2 would also exist these are called "congugate" roots. All the solutions would be x=-2,-1,1,2.

I hope this helps
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk