Hi

first car cost him 2000 more than twice the price of the second car

Let x and (2x + 2000) represent the prices of the second and first car respectitvely

Question states***

  x  + (2x + 2000) = $14,000

      3x = 12,000

       x = $4,000, the second car.  The first car $10,000,    (2*$4000 + $2000)



In reply to Your question:One may, in an example like this..

try various combinations adding up to $14,000,finding the one combination that

 satisfies the criteria of one being $2000 more than twice the other.

Like $10,000 and $4,000 do. 

However, using the criteria and assigning the x and (2x+2000)FIRST

and then putting those together for the sum...is the 'fastest and surest' way

   

RELATED QUESTIONS

Hi I also don't understand how to do this its very confusing

Two junked cars were sold  (answered by solver91311)

Two cars where sold at auction to a buyer who paid a total of $2000.00 for both cars. If... (answered by stanbon)

Michael bought two used cars and fixed them up. He sold the first one for a 35% profit... (answered by ankor@dixie-net.com)

Students are traveling in two cars to a football game 135 miles away. The first car... (answered by ankor@dixie-net.com)

Betty bought a car which was $1543.00 more than the other car that Joan bought. Paula... (answered by oberobic)

Two cars start traveling at the same time. The first car travels 120 miles in the same... (answered by josgarithmetic,addingup)

Two cars left daisy's Diner at the same time and traveled in opposite directions. One car  (answered by ptaylor)

The sum of the speeds of two cars is 724.3 mph.  If the speed of first car is 7.7 faster... (answered by Cromlix)

two cars left daisy's diner at the same time and traveled in opposite directions. one car  (answered by ankor@dixie-net.com)