SOLUTION: A= 2, b = 3, c = 4, d = 5
3ab + 2cd =?
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Question 433338: A= 2, b = 3, c = 4, d = 5
3ab + 2cd =?
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"A= 2, b = 3, c = 4, d = 5
3ab + 2cd =?"
3ab + 2cd
= 3(2)(3) + 2(4)(5) {substituted the values in for the variables}
= 18 + 40 {multiplied through}
= 58 {added 18 and 40}
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