Hi

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.  

Line Perpendicular to 3x+4y=12   and passes through   (7,1)

3x+4y=12 OR y = (-3/4)x+3 ( m = (-3/4))

NEw Line: Perpendicular Line will have slope that is the negative reciprocal,

 y = (4/3)x + b   |Using ordered pair (7,1) to solve for b

 1 = (4/3)*7 + b  

 -25/3 = b 

  y = (4/3)x - 25/3



 

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