Hi

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.  

Line Perpendicular to y=-x-3   and passes through   (0,0)

 y=-x-3 ( m = (-1/1))

NEw Line: Perpendicular Line will have slope that is the negative reciprocal,

 y = x + b   |Using ordered pair (0,0) to solve for b

 0 = 0 + b  

 0 = b 

  y = x



 

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