SOLUTION: How do you solve for n in p=x+(n-2)y I need to see each step on how to solve this. And it would be nice if you could explain why you did each step. Thank you very much.

Algebra ->  Algebra  -> Equations -> SOLUTION: How do you solve for n in p=x+(n-2)y I need to see each step on how to solve this. And it would be nice if you could explain why you did each step. Thank you very much.       Log On

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Question 43184: How do you solve for n in p=x+(n-2)y
I need to see each step on how to solve this. And it would be nice if you could explain why you did each step. Thank you very much.
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
p+=+x+%2B+%28n-2%29y
p+-+x+=+x+-+x+%2B+%28n-2%29y because 2 = 2 can be: 2 - 2 = 2 - 2 as 0 = 0
p+-+x+=+%28n+-+2%29y
%28p+-+x%29%2Fy+=+%28n+-+2%29y%2Fy you need to remove the y so it is not distributed
%28p+-+x%29%2Fy+=+n+-+2
%28p+-+x%29%2Fy+%2B+2+=+n+-+2+%2B+2
%28p+-+x%29%2Fy+%2B+2+=+n