SOLUTION: A point moves in a straight line such that its acceleration a is given by a=2(4-t)^1/2, 0≤t≤4. If it starts at rest, find an expreesion fot the velocity v where a =dv/d
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Question 430896: A point moves in a straight line such that its acceleration a is given by a=2(4-t)^1/2, 0≤t≤4. If it starts at rest, find an expreesion fot the velocity v where a =dv/dt.
Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Solution:The acceleration is, , where, 0≤t≤4
To find the velocity of the point, we integrate the acceleration:
= Substitute u=4-t then, du=-dt and dt=-du.
=
, at (0, 4)
Substitute and have: 0-(-4/3)(4)^(2/3)=32/3 m/s.
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