SOLUTION: 2 over c^2d + 7 over cd^3= unlike denominators
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Question 42928
:
2 over c^2d + 7 over cd^3=
unlike denominators
Answer by
fractalier(2101)
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Here we need to convert each to the lowest common denominator, which is c^2d^3, so we get
2 / c^2d + 7 / cd^3 =
2d^2 / c^2d^3 + 7c / c^2d^3 =
(2d^2 + 7c) / c^2d^3
