SOLUTION: did i do this right? rounded 2 decimal places the approximate x intercept of the equation x^3+14.2x^2-4.8x-12.4=0 in standard window i got 53.44??????????????

SOLUTION: did i do this right? rounded 2 decimal places the approximate x intercept of the equation x^3+14.2x^2-4.8x-12.4=0 in standard window i got 53.44??????????????

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Question 42776: did i do this right?
rounded 2 decimal places the approximate x intercept of the equation x^3+14.2x^2-4.8x-12.4=0
in standard window
i got 53.44??????????????
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
NO ANSWER IS ABOUT X=1.07184�CHECK�.
X^3= 1.231
14.2*X^2= 16.314
-4.8X= -5.145
-12.4= -12.400
TOTAL= 0.000
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