You can
put this solution on YOUR website!Let x be the speed of one train and x+1 min --> x+60 be the speed of the other train on parallel track.
EQUATION:

80[(x+60)-(x)]=3[(x+60)(x)]
x=20
20+60=80
Hence, the speed of one train is 20m/s and the speed of the other is 80m/s.
Paul.