SOLUTION: How many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? Show you process.
Thank you!!
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Question 423888: How many liters of a 14% alcohol solution must be mixed with 20 L of a 50% solution to get a 30% solution? Show you process.
Thank you!!
Answer by dnanos(83) (Show Source): You can put this solution on YOUR website!
let x litters of the 14% solution.
Then we obtain x+20 litters of the 30%.
The pure alcohol litters before and after mixing must be equal.
So we obtain an equation
Multiply by 100
Divide by 16
x=25
So 25 litters 14% needed.
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