SOLUTION: I'm homeschooled and I can't seem to get the steps of this problem.
The question is:
Which statement describes the graph of the equation x^2 + y^2 + 4x - 6y - 3 = 0
The a
Algebra.Com
Question 422050: I'm homeschooled and I can't seem to get the steps of this problem.
The question is:
Which statement describes the graph of the equation x^2 + y^2 + 4x - 6y - 3 = 0
The answer is:
A circle with center (-2, 3) and radius 4.
I'm unsure how to get that answer.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Complete the square:
Constant term to the RHS:
Group like variables:
Divide the first degree x term coefficient by 2, square the result, and add that result to both sides:
Repeat for the first degree y term:
Factor the two perfect square trinomials in the LHS and collect terms in the RHS.
^2\ +\ (y\ -\ 3)^2\ =\ 16)
The equation of a circle with center at )
and radius 
is:
^2\ +\ (y\ -\ k)^2\ =\ r^2)
So re-write your equation:
\right)^2\ +\ \left(y\ -\ 3\right)^2\ =\ 4^2)
John
My calculator said it, I believe it, that settles it
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