SOLUTION: 2x^2-7x=4

Question 412820: 2x^2-7x=4
Answer by shree840(260) (Show Source): You can put this solution on YOUR website!
2X^2-7x=4
2x^2-7x-4=0 you need to multiply 2 with 4 =8 and find factors of 8
8x1
4x2
in this case we can use -8 and 1 so that when added is -7 and multiplied is -
2x^2-8x +x-4
2x(x-4)+ 1(x-4)
(2x+1)(x-4)=0
for the product to be 0 either first group is 0 or 2nd gr is zero
if first gr is 0 then 2x+1=0 orx=-1/2
if 2nd gr is 0 then x-4=0 or x=4
RELATED QUESTIONS
2x^2-7x=4 (answered by jim_thompson5910,edjones)

{{{ (2x^2-7x+4) }}} (answered by richwmiller)

2x^2+7x-4=0 (answered by xcentaur)

Factoring 2x^2 - 7x... (answered by elima)

2x^2-7x-4=0 (answered by checkley79)

0=2x^2+7x-4 (answered by ramkikk66)

Solve 2x^2+... (answered by MathLover1)

h(x)=2x^4-7x^3+4x^2+7x-6 (answered by Fombitz)

Solve for x. 2x^2 - 7x =... (answered by scott8148)