SOLUTION: Trains A and B are traveling in the same direction on parellel tracks. Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h. Train A passes t
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Question 406733: Trains A and B are traveling in the same direction on parellel tracks. Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h. Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m. At this rate, what time will Train B catch up to Train A?
Found 2 solutions by ankor@dixie-net.com, Alan3354:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h.
Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m.
At this rate, what time will Train B catch up to Train A?
:
from the given information, we know that train B is 30 min (1/2 hr) behind
train A, when train A passes the station at 2:25PM
:
The distance between the trains at this time: * 50 = 25 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 25 mi
50t = 40t + 25
50t - 40t = 25
10t = 25
t =
t = 2.5 hr or 2 hr 30 min
:
2:25 PM + 2:30 = 4:55 pm, B catches A
:
:
Check this by finding the travel distance of each train:
Train B: 50*2.5 = 125 mi
Train A: 40*2.5 = 100 mi
-------------------------
dif in distance: 25 mi
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Trains A and B are traveling in the same direction on parellel tracks. Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h. Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m. At this rate, what time will Train B catch up to Train A?
-----------------
Train A is 20 miles away when train B passes the station (0.5 hr * 40 mph)
Train B gains on train A at 10 mph (50 - 40)
20 mi/10 mph = 2 hours to catch up
2:55 + 2 = 4:55 PM
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