SOLUTION: Please help :) given: u = sqrt(x^2+y^2) solve: [(du/dx)/(du/dy)]

Question 404132: Please help :)
given: u = sqrt(x^2+y^2)
solve: [(du/dx)/(du/dy)]
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
given: u = sqrt(x^2+y^2)
solve: [(du/dx)/(du/dy)]
-------
du/dx = (1/2)(2x)/sqrt(x^2+y^2) = x/sqrt(x^2+y^2)
-------
du/dy = (1/2)(2y)/sqrt(x^2+y^2) = y/sqrt(x^2+y^2)
----
Ans: x/y
=====
Cheers,
Stan H.
==========
RELATED QUESTIONS
given: u = √(xy) solve:... (answered by richard1234)

Hi Please can someone help 10. If u = ax + by and v = bx - ay, a and b... (answered by richard1234)

I need some help please :) solve: du/dx = x/y and/or solve: du/dx = y/x (answered by richard1234)

Suppose y=x/u, where u is a function of x. Show that y(du/dx)+ u(dy/dx)=1 Thanks!! (answered by jsmallt9)

lease help me solve this equation: Differentiate the following functions. DO NOT... (answered by Fombitz)

I have 2 indefinite integral problems I am struggling with, please help me if you can. (answered by bucky)

Let Y = X^2 where X is U(a,b), 0<=a (answered by CPhill)
I need help with this: Integrate: {{{(-1/u + u^2 + 1)}}}du (answered by Alan3354)
Hello! I am trying to figure out these integrals but I keep getting stuck. (also, not... (answered by richard1234)