SOLUTION: The perimeter of a rectangle is 76m. If the width were doubled and the length were increased by 5 m, the perimeter would be 120m. What are the length and width of the original rec
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Question 403285: The perimeter of a rectangle is 76m. If the width were doubled and the length were increased by 5 m, the perimeter would be 120m. What are the length and width of the original rectangle?
Answer by Tatiana_Stebko(1539) (Show Source): You can put this solution on YOUR website!
If L is the length, W is the width
Perimeter of the rectangle is , so .
If the width be double (2W) and the length ne increase by 5 m (L+5)? the perimeter will be
Equation system
.
.
From the second equation we subtract the first equation
.
If from the first equation will have
So the length is 21m and the width is 17m
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