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1/2q - 6 = 1/5q
let's get rid of those fractions by multiplying moth sides by the LCD of 10;
10.(1/2q - 6) =10.( 1/5q )
5q-60=2q add additive inverse of 2q to both sides;
3q-60=0 add additive inverse of -60 to both sides;
3q=60 divide both sides by 3;
0.5b + 3.4 = 0.2b + 12.4
Let's multiply both sides by 10 to eliminate the decimals;
3b=90 divide both sides by 3;
4x - 2 = -8 + 5x
get the variables on the same side by adding additive inverse of 5x to both sides.
4x - 2-5x = -8 + 5x-5x
-x-2=-8 add additive inverse of -2 to oth sides to leave the variable, which is x, alone;
-x=-6 divide both sides by -1;
3 - 3(5 - x) = 0
3x=12 divide both sides 3;
This equation is a conditional equation. A conditional equation is an equation that is not true for all real numbers but has at leat one real number solution.
-3 - 4(t - 5) = -2(t + 3) + 11
-2t=-12 divide both sides by -2