SOLUTION: help please and thank you simplify by removing factors of 1 (x^2-64)/(8-x)

Algebra.Com
Question 392558: help please and thank you
simplify by removing factors of 1
(x^2-64)/(8-x)

Answer by haileytucki(390)   (Show Source): You can put this solution on YOUR website!
(x^(2)-64)/(8-x)
The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
((x-8)(x+8))/(-x+8)
Factor the expression.
((-1)(-x+8)(x+8))/(-x+8)
Reduce the expression by canceling out the common factor of (x-8) from the numerator and denominator.
((-1)(x-8)(x+8))/(-x+8)
Reduce the expression by canceling out the common factor of (x-8) from the numerator and denominator.
(-1)(x+8)
Multiply each term in the first polynomial by each term in the second polynomial.
(-1*x-1*8)
Multiply -1 by each term in x+8 to get -x-8.
(-x-8)
Remove the parentheses around the expression -x-8.
-x-8

RELATED QUESTIONS

Can you please show me step by step how to simplify this equation by removing factors of... (answered by Fombitz)
Simplify by removing factors of 1 x^2-7x+12/x^2+5x-36 Can you please show me how to (answered by Fombitz)
Please help..... Simplify by removing factors of 1: m^2-36/(m+6)^2 mulitply and... (answered by checkley77)
simplify by removing factors of 1.... (answered by user_dude2008)
Simplify by removing factors of 1 (z^2-64)/(8-z) the simplified form is (answered by user_dude2008)
simplify by removing factors of 1... (answered by user_dude2008)
Please help with these. I am having a hard time understanding, especially the dividing! (answered by KMST)
Simplify by removing factors of 1... (answered by stanbon)
Please help solve the following. Please show how you came up with the answer so I can see (answered by Alan3354)