SOLUTION: hello, I really need help in solving these two equations. The question is as following: write the following as a single power, then evaluate. (-32)^3/5 x (-32)^4/5 / (-32)^2/5

Question 389243: hello,
I really need help in solving these two equations. The question is as following:
write the following as a single power, then evaluate.
(-32)^3/5 x (-32)^4/5 / (-32)^2/5
and
4096^3/4 / 4096^2/3 x 4096^5/6
thanking you in advance!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write the following as a single power, then evaluate.
(-32)^3/5 x (-32)^4/5 / (-32)^2/5
---
= (-32)^[3/5 + 4/5 - 2/5]
---
= (-32)^[5/5]
--
= -32
==================================
and
4096^3/4 / 4096^2/3 x 4096^5/6
---
= 4096^[3/4 + 2/3 + 5/6]
---
= 4096^[(9+8+10)/12]
---
= 4096^(27/12)
---
= 2^27
---
Cheers,
Stan H.

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