SOLUTION: suppose you need to solve a system of two equations in which one equation is y=(x+2)(x-3)(x-6) and the other equation represents a horizontal line. how many solutions could your sy

SOLUTION: suppose you need to solve a system of two equations in which one equation is y=(x+2)(x-3)(x-6) and the other equation represents a horizontal line. how many solutions could your sy

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Question 382063: suppose you need to solve a system of two equations in which one equation is y=(x+2)(x-3)(x-6) and the other equation represents a horizontal line. how many solutions could your system have?

Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
We have y = (x+2)(x-3)(x-6) = C, for some constant C. This turns into a cubic which has at most three real solutions for x.
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