SOLUTION: Hello,
I'm seeking help with the following math problem below, a tutor helped me before with this same problem but I still don't understand. Any help would be appreciated.
Algebra.Com
Question 380937: Hello,
I'm seeking help with the following math problem below, a tutor helped me before with this same problem but I still don't understand. Any help would be appreciated.
(1/2)a + (3/4)b - c
when a=8, b=4 and c=-2
Thank You!
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
your problem is stated as:
(1/2)a + (3/4)b - c
when a=8, b=4 and c=-2
your given expression is (1/2)*a + (3/4)*b - c
you simply substitute the numbers for the letters.
your expression becomes (1/2)*8 + (3/4)*4 - (-2).
(1/2) * 8 = 4
(3/4) * 4 = 3
your expression becomes 4 + 3 - (-2).
simplify this by combining like terms to get 4 + 3 - (-2) = 7 - (-2).
Subtracting a negative number is equivalent to adding a positive number.
Your expression becomes 7 + 2.
Combine like terms again to get 7 + 2 = 9.
Your expression becomes 9.
That's your answer.
If you're still confused, send me an email with follow up questions as to which part confuses you.
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