SOLUTION: find the solution of the following differential equations:
1. dy/dx= te^y, y(1)=0
2. x^2y'+2xy=cosx
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Question 378889: find the solution of the following differential equations:
1. dy/dx= te^y, y(1)=0
2. x^2y'+2xy=cosx
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
1. Is a constant?
Or should that be an .
.
.
.
2.
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