SOLUTION: How many real solutions does the following problem have? Log(4x^2+4x+101)=2

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Question 375426: How many real solutions does the following problem have?
Log(4x^2+4x+101)=2
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!







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1 solution, a double root at

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

Log(4x^2+4x+101)=2



10^2 = 4x^2 + 4x + 101

100 = 4x^2 + 4x + 101

0 = 4x^2 + 4x + 1

factoring

(2x + 1)(2x + 1)= 0 Note: the SUM of inner product(2x) and outer product(2x) = 4x

2x + 1 = 0

x = (-1/2)

there is only one real solution 

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