SOLUTION: The cost of the gold bracelet was20.00 dollars more than three times the silver one.Together they cost 320.00dollars. How much did each cost?

Algebra.Com
Question 373364: The cost of the gold bracelet was20.00 dollars more than three times the silver one.Together they cost 320.00dollars. How much did each cost?
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
silver = s
gold = 3s + 20. also, s+3s+20 = 320. Then
4s + 20 = 320,
4s = 300,
s = 75, the cost of the silver bracelet.
3s + 20 = 245, the cost of the gold bracelet.

RELATED QUESTIONS

The cost of the gold bracelet was $20.00 more than three times the silver one. Together... (answered by checkley77)
The cost of the gold bracelet was $20.00 more than three times the silver one. Together... (answered by checkley77)
a gold bracelet cost $20 more than ten times the cost of silver earrings. the cost of... (answered by fractalier)
A person wants to make a one ounce ring composed of Gold and Silver. One ounce of gold... (answered by stanbon)
Together, a neckless and a bracelet cost $192. find the price of each if the neckless... (answered by HyperBrain)
One number is 6 more than another. The sum of the numbers is 30. Find the numbers. A (answered by College Student)
A bat and ball together cost $31.00. The bat costs $15 more than the ball. What is the... (answered by Alan3354,ikleyn)
Bruce bought two books. One book cost four dollars more than three times the other.... (answered by reviewermath,Boreal,addingup)
Marina has a gold bracelet that weighs 90 grams. 45% of the bracelet is pure gold. How... (answered by ikdeep)