SOLUTION: Factor completely: y^4-1 I am not sure how to factor this. Thank you.

Algebra.Com
Question 371369: Factor completely: y^4-1 I am not sure how to factor this. Thank you.
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
It's a difference of two squares.

The first factor is also a difference of two squares.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi,

Factoring completely

y^4-1

(y^2 -1)(y^2 +1)

(y-1)(y+1)(y^2+ 1) 

RELATED QUESTIONS


How do I factor this completely?
y^4Z^4-81z^4  Thank you in... (answered by stanbon)

I am not sure how to factor this problem:... (answered by jsmallt9)

Factor completely Please show work as I am not sure how to do this.
9t2 + 14t +... (answered by Alan3354)

Factor completely:

5y^9 - 53y^6 + 72y^3. 

I think that this problem has to do with... (answered by jim_thompson5910)

Factor completely, if polynomial is prime state it

4x^2 - 25


I am not quite sure... (answered by nerdybill,Earlsdon)

I need to factor this problem completely, not quite sure how to though.... (answered by Alan3354)

Can you explain how to solve this in detail? Thank you.

  Factor completely:
   4x2 –  (answered by elima)

Good Evening Tutor, 

I am not sure how to solve this problem can you help?  

Factor  (answered by stanbon)

this equation is asking to factor completely 
ax-ay+x^2-xy

please help,I am not sure... (answered by jim_thompson5910)