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put this solution on YOUR website!lines are shown below:
2x-4y=6...................................I
3x+y=-5.............................II
What are the coordinates of the point of intersection?
WE HAVE TO SOLVE THE 2 EQNS.AS THE POINT OF INTERSECTION SHOULD LIE ON BOTH LINES AND HENCE SHOULD SATISFY BOTH EQNS.
EQN.I+EQN.II*4..GIVES
2X-4Y+12X+4Y=6-20=-14
14X=-14
X=-1................SUBSTITUTING IN EQN.II
3*(-1)+Y=-5
-3+Y=-5
Y=-5+3=-2
HENCE POINT OF INTERSECTION IS (-1,-2)