SOLUTION: what is x 6x+4=5(3x+8) what is y -2(18-3y)=7y+2y what is w 9(2+w)-4w=3w-10 what is d 3 (4d+1)-9d=6(2-d) what is x -14 +3 (x+10)=7(2x+4)=x

Question 368817: what is x 6x+4=5(3x+8)
what is y -2(18-3y)=7y+2y
what is w 9(2+w)-4w=3w-10
what is d 3 (4d+1)-9d=6(2-d)
what is x -14 +3 (x+10)=7(2x+4)=x
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started.

# 1

Start with the given equation.

Distribute.

Subtract from both sides.

Subtract from both sides.

Combine like terms on the left side.

Combine like terms on the right side.

Divide both sides by to isolate .

Reduce.

-------------------

Answer:

So the solution is

================================================================
# 2

Start with the given equation.

Distribute.

Combine like terms on the right side.

Add to both sides.

Subtract from both sides.

Combine like terms on the left side.

Divide both sides by to isolate .

Reduce.

----------------------------------------------------------------------

Answer:

So the solution is

If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim
RELATED QUESTIONS
8x - 9x + 2(-3s - 4) if x=-8 -4(4 + 7y) + 5 + 3y if y=2 5(-m - 3) + 4m - 10 if m=-5 (answered by solovelyy<3)

I've missed a lot of school because I've been sick and I'm trying to get all of my work... (answered by jsmallt9)

By the notation n (d) , we mean an n-digit number consisting of n times of the digit d.... (answered by greenestamps)

What is the solution to 1. y = 3x � 8 y = 4 � x 2. x + y = 0 3x + y = -8 (answered by Alan3354)

What is the value of w in the equation 3/4w + 8=... (answered by rfer)

what is the equation of the line that passes through (�2, 4) and is perpendicular to 6x + (answered by josgarithmetic,MathTherapy)

what is the indicated product or this 1- 2s(s-4) 2- (w+7)(w+3) 3- (x+9)(x-2) 4-... (answered by math_helper)

Very Important I can get someone to check these for m... I have to get an A, and I was... (answered by shree840)