SOLUTION: Hi there, I have to find the quadratic equation that has vertex (-1, -3) and y-intercept (0, 1). I plugged the vertex into the vertex form and got {{{a(x + 1)^2 - 3}}} The

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Question 367166: Hi there, I have to find the quadratic equation that has vertex (-1, -3) and y-intercept (0, 1).
I plugged the vertex into the vertex form and got

Then I plugged in the given y-intercept and solved for a


So my vertex form will be . Converting this to general form...



Did I do this correctly? I've never seen a problem like this and couldn't find an example in the book. Thanks for your time and have a good day :)
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi, 

Proceeded exactly as one should.

If you have used the correct value for the y-intercept. all's well.

**Listed is a y-intercept (0,1)



a = 4

vertex form

y = 4*(x+1)^2 - 3

general form

4x^2 + 8x + 1 

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