SOLUTION: simplify: (x^2-6x+8)/(x^2+3x-28) *(x^2+6x-7)/(x^2-3x+2)

Question 36422: simplify: (x^2-6x+8)/(x^2+3x-28) *(x^2+6x-7)/(x^2-3x+2)
Found 2 solutions by ilana, vidhyak:
Answer by ilana(307) (Show Source): You can put this solution on YOUR website!
Oh, I love when this happens!! It equals 1!
You factor each polynomial. (x^2-6x+8)=(x-2)(x-4), (x^2+6x-7)=(x+1)(x-1), (x^2+3x-28)=(x+7)(x-4), (x^2-3x+2)=(x-2)(x-1). so, the numerator and denominator all have the same terms, and they all cancel out.
Answer by vidhyak(98) (Show Source): You can put this solution on YOUR website!
(x^2-6x+8)/(x^2+3x-28) *(x^2+6x-7)/(x^2-3x+2)
(x^2-6x+8) can be written as (x-4)(x-2)
(x^2+3x-28) can be written as (x+7)(x-4)
(x^2+6x-7) can be written as (x+7)(x-1)
(x^2-3x+2) can be written as (x-2)(x-1)

((x-4)(x-2))/((x+7)(x-4)) * ((x+7)(x-1))/((x-2)(x-1))

Writting the numerator and denominatiors separately

(x-4)(x-2)(x+7)(x-1)
---------------------
(x+7)(x-4)(x-2)(x-1)
Cancelling out the common terms you get 1

Answer is 1
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