SOLUTION: -3(b-8)-5+9(b+2)=1

Algebra.Com
Question 361650: -3(b-8)-5+9(b+2)=1

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given equation.


Distribute.


Combine like terms on the left side.


Subtract from both sides.


Combine like terms on the right side.


Divide both sides by to isolate .


Reduce.


----------------------------------------------------------------------

Answer:

So the solution is

RELATED QUESTIONS

-3(b-8)-5=9(b+2)+1 (answered by bonster)
-3(b-8)-5=9(b+2)+1 (answered by bonster)
8-1(3+b)=b+9 (answered by JulietG)
A=[ 5 0 -9       
   -5 6  2] 
  
B=[ 2  7                  
   -2 -4]... (answered by Edwin McCravy,AnlytcPhil)
let A = [3 -8 -5] [-4 -1 5] [-1 -9 -2] and B = [-4 -7 -1] [8 -1 8] [-3 -3 7] (answered by ikleyn)
1/a-b+ 2/b-a+ 3/a-b+ 4/b-a+ 5/a-b+ 6/b-a+ 7/a-b+ 8/b-a= ?/a-b I think the ? mark would... (answered by scott8148)
ε = {1,2,3,4,5,6,7,8,9,10} A = {2,4,6,8,10} B = {1,3,5,7} C = {1,2,4,5,6,8,9,10}... (answered by MathLover1)
1) a=6 b=8 c=? 2) a=? b=12 c=13 3) a=? b=4 c=5 4) 9 21 ? 5) 24 10 ? 6) ? 3 4 (answered by Edwin McCravy,richwmiller)
Let A= [0]  B=[1 2 3]  C=[-3 7]
       [-4]   [0 5 2]    [ 9 8]
       [3]    [0  (answered by Edwin McCravy)