Hi, 

*Note: to get an 'equation' one needs to use a variable

1)Let x represent the number of minutes

At 8 pm, the temperature was 10 degrees Cel,dropping 3 degrees per minute

y = 10°celsius - 3*x

at 8:10, ten minutes will have passed

y = 10°celsius - 3*10min = -20°celsius



2)At 8 p.m., the temperature was 10 degrees Cel., and was dropping 

"d degrees" per minute

y = 10°celsius - d*x min 

7:45 is 15 min earlier

y = 10°celsius - d*(-15)min  = 10°celsius + 15*d 

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