SOLUTION: -4(x-2)+3(x-1)=2(x-7)-5
Algebra.Com
Question 359170: -4(x-2)+3(x-1)=2(x-7)-5
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
-4(x-2)+3(x-1)=2(x-7)-5
-4x + 8 + 3x - 3 = 2x - 14 - 5
-x + 5 = 2x - 19
-x - 2x = -19 - 5
-3x = -24
x = -24/-3
x = 8
RELATED QUESTIONS
1/5(x+3)-4=1/2(x+7) (answered by rfer)
5(x-4)=2(x+1)-7 (answered by bacos)
1.(x+7)(x+1)=0
2.(x+2)(x+3)=0
3.x(x-2)=0
4.x(x-7)=0... (answered by MathLover1)
5(x+7)+1=2-(x-3) (answered by Fombitz)
2/7 + 3/5 = X x 3 + 1/2
X = (answered by maranneblas)
1. Solve Solve 4^x = 12.
2. Solve 5^(x + 5)= 9^x.
3. Solve 4^(x + 7) = 6^(x – 1).
(answered by lwsshak3)
Solving Exponential Equations Using Logarithms?
2^x = 30
5^x - 1 = 3^x
3.53^(x+1)... (answered by edjones)
(4/x+3)-x+1/(x^2-4x-21)=... (answered by stanbon)
2/3(x+5)-1=4-x (answered by rfer,MathTherapy)