SOLUTION: 2x-y-3z=1, 4x+3y+2z=-4, -3x+2y+5z=-3 solve for x,y, and z

Algebra.Com
Question 356625: 2x-y-3z=1, 4x+3y+2z=-4, -3x+2y+5z=-3 solve for x,y, and z
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
[A]=
[x]=
[b]=
.
.
.
[A][x]=[b]
[x]=[A]inv[b]
.
.
.
det[A]=
.
.
.
[A]inv=
.
.
.
[x]=[A]inv[b]=
[x]=

RELATED QUESTIONS

2x + 3z = 4 3y + 2z = 5 3x + 4y = −16 (x, y, z) = 2x +... (answered by Alan3354)
3x – 2y + 3z = 8 2x + y – z = 1 4x – 3y + 2z = 4 solve by... (answered by richwmiller)
Solve by substitution or elimination: 2x-3y+z=14 4x+2y-5z=-3... (answered by elima)
Solve. If the system's equations are dependent or it there is no solution, state this. (answered by Alan3354)
Solve. If the system's equations are dependent or it there is no solution, state this. (answered by solver91311)
2x +y - z=4,3x +5y +z=16,x-2y-5z=3. x+2y+z=4,x+3y-2z=2 , 3x +y+2z =6 c (answered by Alan3354)
x-2y+3z = - 4 3x+y-z=0 2x+3y-5z=1 gauss jordan... (answered by Cromlix)
2x+3y-z=4 3x+2y+2z=6 4x-y+3z=5 solve in three... (answered by josmiceli)
solve using the substitution method problem 2x-y-z=15 4x+5y+2z=10 (answered by Edwin McCravy)