SOLUTION: How many milliliters of a 8% alcohol solution must be added to 12 milliliters of a 33% alcholol solution to produce a 20% alcohol solution?
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Question 354807: How many milliliters of a 8% alcohol solution must be added to 12 milliliters of a 33% alcholol solution to produce a 20% alcohol solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.33*12+.08*X=.20(12+X)
3.96+.08X=2.4+.20X
.08X-.20X=2.4-3.96
-.12X=-1.56
X=-1.56/-.12
X=13 ML. OF 33% SOLUTION.
.33*12+.08*13=.20(12+13
3.96+1.04=.20*25
5=5
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