SOLUTION: Can you please help me with this equation: 6y+7=3=2(y-4)
I tried: 6y+7=3=2(y-4)
=6y+7=3+2y-8
=6y-2y=3-8-7
=4y/4 = -12/4
y=-3
But it wasn't the
Algebra.Com
Question 35157: Can you please help me with this equation: 6y+7=3=2(y-4)
I tried: 6y+7=3=2(y-4)
=6y+7=3+2y-8
=6y-2y=3-8-7
=4y/4 = -12/4
y=-3
But it wasn't the right answer, please tell me what I did wrong.
Thank you very much!
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
YOU HAVE TOO MANY = SIGNS. REDO/CORRECT AND I'LL SOLVE YOUR PROBLEM.
RELATED QUESTIONS
Can you please help me with this equation:... (answered by checkley71)
Could you please help me find the inverse of the following function?
f(x) =... (answered by lwsshak3)
Please, help me with this problem:
Simplify this expression sqrt x^8 y^7 z^2
a.... (answered by ankor@dixie-net.com)
Please tell me the problem with this equation.
4y - (4+y) + 24=6y + 20 + 4y
4y - 4y +... (answered by sudhanshu_kmr)
2y^4-y^3-6y^2 (answered by checkley77)
please help me
y^2 /y-4 - 4/y-4
y^3-5y /6y - y^3+y+3/6y
(answered by stanbon)
please help me add or subtract the following
1) z+3/2+ 7/2
2) 3/z- z-4/z
3)... (answered by jim_thompson5910)
6y-16=4(y-3) (answered by Tatiana_Stebko)
Match the expressions with the nonpermissible replacements for y.
Y^2-2y+1 / 2y-3. Y... (answered by stanbon)