SOLUTION: The length of a rectangle is 6 in. greater than the width. The perimeter of the rectangle is 24 in. Find the demensions of the rectangle. How would I write out the equation? I b

Question 345959: The length of a rectangle is 6 in. greater than the width. The perimeter of the rectangle is 24 in. Find the demensions of the rectangle.
How would I write out the equation? I believe the answer to be the length is 9 and the widt is 3...
Answer by haileytucki(390) (Show Source): You can put this solution on YOUR website!
2*X+2(X+6)=24
Multiply 2 by X to get 2X.
2X+2(X+6)=24
Multiply 2 by each term inside the parentheses.
2X+2X+12=24
Since 2X and 2X are like terms, add 2X to 2X to get 4X.
4X+12=24
Since 12 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 12 from both sides.
4X=-12+24
Add 24 to -12 to get 12.
4X=12
Divide each term in the equation by 4.
(4X)/(4)=(12)/(4)
Simplify the left-hand side of the equation by canceling the common factors.
X=(12)/(4)
Simplify the right-hand side of the equation by simplifying each term.
X=3
Now, plugging your answer of 3 into (x+6)= 9
Answers, 3,9
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