SOLUTION: A theater owner want to divide an 1800 seat theatre in 3 sections. With tickets costing 20, 35, and 50. He wants to have twice as many 20 dollar tickets as the sum of the other tic

Question 345374: A theater owner want to divide an 1800 seat theatre in 3 sections. With tickets costing 20, 35, and 50. He wants to have twice as many 20 dollar tickets as the sum of the other tickets and he wants to earn 48,000 from a full house. To find out how many seats in each section, solve the equations.
x+y+z=1800
x=2(y+z)
20x+35y+50z=48,000
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Substitute into eq. 1 and eq. 2,
1.
1.
1.
1.
.
.
.
2.
2.
2.
2.
From eq. 1,

Substitute into eq. 2,

Then,

And finally,

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