SOLUTION: How do I solve the equation, {{{2/(x+4) +1}}} = {{{12/(x^2+9x+20)}}} ? 2/(X+4) + 1 = 12/(X^2+9X+20) 1={12/{(X+5)(X+4)} *(X+4)/2] 1=[{12 (X+4) }/{2(X+4)(X+5)}] � (

Question 337477: How do I solve the equation, = ?
2/(X+4) + 1 = 12/(X^2+9X+20)
1={12/{(X+5)(X+4)} *(X+4)/2]
1=[{12 (X+4) }/{2(X+4)(X+5)}] �
(X+4) IS CANCEL AND 12/2 IS 6
1*(X+5)=[6(1/(X+5)) *(X+5)] MULTIPLY THE INVERSE
1*(X+5) = 6 SUBTRACT BOTH SIDES WITH 5
X+5-5 = 6-5
X=1
Answer by chiexpert(48) (Show Source): You can put this solution on YOUR website!
2/(X+4) + 1 = 12/(X^2+9X+20)
1={12/{(X+5)(X+4)} *(X+4)/2]
1=[{12 (X+4) }/{2(X+4)(X+5)}] �
(X+4) IS CANCEL AND 12/2 IS 6
1*(X+5)=[6(1/(X+5)) *(X+5)] MULTIPLY THE INVERSE
1*(X+5) = 6 SUBTRACT BOTH SIDES WITH 5
X+5-5 = 6-5
X=1
RELATED QUESTIONS
(x)/(x^(2)+9x+20)-(4)/(x^(2)+7x+12) (answered by stanbon)

-1/4(x-12)+1/2(x=2)-x+4 (answered by stanbon)

(((x+1/x+4 + x-3/x+5 = (2x^2+6x+11)/(x^2 +... (answered by edjones)

1/x+5+3/x+4=-1/x^2+9x+20 what is the... (answered by sofiyac)

1/4... (answered by rothauserc)

I need help to solve this equation 1/x+5 + 3/x+4 =... (answered by edjones)

solve equation:... (answered by Fombitz)

1) 24xy^3+30x^2y-12x^3y^3 2)x^2+5x-24 3)3y^2+7y+4 4)3y^2-108 5) x^2+4x+x+4 (answered by Fombitz)

how do you solve the following equations, 3/4x-1/3x+5=5/6x... (answered by Fombitz)