SOLUTION: Please help me write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8. please and thank you

Question 333064: Please help me write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8.
please and thank you
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
write the equation of the line in slope intercept form through the point coordinates (-4,6) and perpendicular to 3x-2y=8.
:
Find the slope by putting the equation into the slope/intercept form (y=mx+b)
3x - 2y = 8
-2y = -3x + 8
y has to be positive, multiply by -1
2y = 3x - 8
divide both sides by 2
y =
y = x - 4
Slope: m1 =
;
slope relationship of the slopes of perpendicular lines is m1*m2 = -1
find m2
*m2 = -1
m2 = -1 *
m2 = is the slope of the perpendicular line
:
Find the equation using the point/slope form: y - y1 = m(x - x1)
m = , x1 = -4, y1 = 6
y - 6 = (x - (-4))
y - 6 = (x + 4)
y - 6 = x + (-2/3)*4
y - 6 = x -
y = x - + 6
y = x - +
y = x + is the equation of the perpendicular line
:
:
Check by finding y when x = -4
y = (-4) +
y = +
y =
y = 6

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