SOLUTION: x^2-16<= 0
Algebra.Com
Question 332530: x^2-16<= 0
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Find the roots.
root at x = 4 and x = -4
Now pick a value less than -4. let's say -10.
When x=-10, then which is > 0
Pick a value between the two root. Say x=0
When x=0 which is < 0
Pick a value greater than 4, say 10
Again which is greater than 0.
So points to the left of -4 and to the right of 4 do not satisfy the inequality.
The plot will be all points above the curve x^2-16 and below the x axis, between -4 and 4
See this URL for a plot
http://www.wolframalpha.com/input/?i=x^2-16%3C%3D0
RELATED QUESTIONS
Solve... (answered by jim_thompson5910)
x^2+6x-16=0 (answered by ewatrrr,unlockmath,MathLover1)
x^2 = 16
y^2 + 8y =... (answered by stanbon)
Solve. x^2 – 10x + 16 =... (answered by Fombitz)
Solve... (answered by jim_thompson5910)
x^4-17x^2+16=0 (answered by stanbon)
x^2+4x-4y+16=0 (answered by checkley77)
4x^2+x-1/16=0... (answered by checkley77)
x^4-8x^2+16=0 (answered by nerdybill)