# SOLUTION: what is the y coordinate of the vertex of a parabola wit the following equation? y=x^2-6x+14

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 Question 332331: what is the y coordinate of the vertex of a parabola wit the following equation? y=x^2-6x+14Found 2 solutions by nerdybill, solver91311:Answer by nerdybill(7009)   (Show Source): You can put this solution on YOUR website!y=x^2-6x+14 . The 'x' coordinate of the vertex can be found by: x = -b/(2a) x = -(-6)/(2(1)) x = 6/2 x = 3 . To find the 'y' coordinate, plug it back into the original equation: y=3^2-6(3)+14 y=9-18+14 y = 5 (this is your answer) Answer by solver91311(17077)   (Show Source): You can put this solution on YOUR website! I'll do you one better. I'll tell you how to find the -coordinate of the vertex of any parabola with equation in standard form. Given first find the -coordinate of the vertex using: then evaluate your function for that value of the independent variable: John My calculator said it, I believe it, that settles it