SOLUTION: what is the y coordinate of the vertex of a parabola wit the following equation? y=x^2-6x+14

Question 332331: what is the y coordinate of the vertex of a parabola wit the following equation?
y=x^2-6x+14
Found 2 solutions by nerdybill, solver91311:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
y=x^2-6x+14
.
The 'x' coordinate of the vertex can be found by:
x = -b/(2a)
x = -(-6)/(2(1))
x = 6/2
x = 3
.
To find the 'y' coordinate, plug it back into the original equation:
y=3^2-6(3)+14
y=9-18+14
y = 5 (this is your answer)

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

I'll do you one better. I'll tell you how to find the -coordinate of the vertex of any parabola with equation in standard form.

Given

first find the -coordinate of the vertex using:

then evaluate your function for that value of the independent variable:

John

My calculator said it, I believe it, that settles it

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