SOLUTION: Solve each equation using quadratic formula.
x^2-3x+2=0
y^2+y=6
Algebra.Com
Question 331886: Solve each equation using quadratic formula.
x^2-3x+2=0
y^2+y=6
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x^2-3x+2=0
a=1,b=-3,c=2
y1=-1+sqrt(1+24)/2
y1=-1+5/2
y1=+2
..
y2= -1-sqrt(1+24)/2
y2=-6/2
y2=-3
RELATED QUESTIONS
Solve each equation using the quadratic formula.
1.x^2+10=-25... (answered by Alan3354)
Please help me answer this.
solve each equation by using the quadratic formula
1.)... (answered by Edwin McCravy)
How do I solve this 2y^2-y=6 quadratic equation using the Quadratic... (answered by jim_thompson5910)
Solve the quadratic equation using the Quadratic Formula:
2y^2-y=6
(answered by jim_thompson5910)
30.) Solve each equation by using the quadratic formula
-3x^2-2x-5=0
(answered by checkley77)
Solve each equation by using the quadratic formula.
30. -3x^2 - 2x - 5 =... (answered by jim_thompson5910)
Solve each equation using the quadratic formula.... (answered by ewatrrr)
x^2+4x-6 (put into vertex form)--> y=(x-h)^2+k
3x^2+6x-3=0 (solve by using quadratic... (answered by josgarithmetic)
Solve using the quadratic formula:... (answered by checkley77)