SOLUTION: Solve.
x^5-5x^3+4x=0
Please help.
Algebra.Com
Question 330334: Solve.
x^5-5x^3+4x=0
Please help.
Answer by trippin on trig(7) (Show Source): You can put this solution on YOUR website!
Try this, 1st factor out one 'x' and get:
x(x^4-5x^2+4)
now factor what remains in the parenthesis and get:
(x^4-5x^2+4)
factor by grouping:
(x^4-4x^2)(-x^2+4)
x^2(x^2-4)-(x^2-4)
(x^2-4)(x^2-1)
bring down the intial x factored out:
ans= x(x^2-4)(x^2-1)
RELATED QUESTIONS
PLEASE Help!!!
Factoring to solve Quadratic Equations.
Use the Zero-Product Property to (answered by checkley71)
Please help me solve this problem.
Solve for x.
4x(x-4)-5x(x-3)=0
thank... (answered by sonya)
Please help me solve... (answered by checkley75)
could someone please help me?
solve by graphing:
x^2-4x+3=0
and... (answered by Nate)
please help??
it says solve by completing the square:
x^2+8x+3=0
x^2+4x+1=0... (answered by stanbon,vleith)
please help these are due today.
solve by substitution.
5x-2y=-5
y-5x=3... (answered by stanbon)
4x(x-1)-5x(x)=3 solve for x
please help and... (answered by nyc_function)
Please help me solve this equation: {{{ sqrt ( 5x+1 ) - sqrt (4x+3) = 0... (answered by mananth)
The question says find the x-intercepts y=4x^2+5x-6
y=4x^2+5x-6
0=4X^2+5X-6... (answered by uma)