SOLUTION: If 3x^2 – 2x + 7 = 0, then (x – 13)^2= I DON'T GET IT ALL CAN YOU HELP ME?

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Question 329788: If 3x^2 – 2x + 7 = 0, then (x – 13)^2=
I DON'T GET IT ALL CAN YOU HELP ME?
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
3x^2 – 2x + 7 = 0, then (x – 13)^2
.
x=1/3 + 2sqrt(5)/3 * i, x= 1/3 - 2sqrt(5)/3 * i [quadratic formula below]
.
((1/3 + 2sqrt(5)/3 * i)-13)^2= 1424/9 - 152sqrt(5)/9 * i ANSWER
((1/3 - 2sqrt(5)/3 * i)-13)^2= 1424/9 + 152sqrt(5)/9 * i ANSWER
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Ed
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -80 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -80 is + or - .

The solution is

Here's your graph:
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